C(Q)=((q^2)/6)+2q+10

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Solution for C(Q)=((q^2)/6)+2q+10 equation: 



()=((C^2)/6)+2C+10

We move all terms to the left:

()-(((C^2)/6)+2C+10)=0



Domain of the equation: 6)+2C+10)!=0

C!=0/1

C!=0

C∈R



We add all the numbers together, and all the variables

-((C^2/6)+2C+10)=0

We multiply all the terms by the denominator


-((C^2=0

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